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Use Theorem 12.33 to find the indicated derivatives in Exercises 27鈥30. Express your answers as functions of two variables.

zwhenz=(x2+xy)ey,x=rcosandy=rsin

Short Answer

Expert verified

The value iszr=r2ersin(sin2+sin2+cos2(rcos+rsin+1)

Step by step solution

01

Step 1. Given Information:

Given:

z=(x2+xy)ey,x=rcosandy=rsin

We have to find the indicated derivatives and express your answers as functions of a single variable.

02

Step 2. Solution:

By Theorem 12.33, we have

z=zxx+zyy---(1)

So first we find zx,x,zyy

So we have

zx=ey(2x+y)zy=eyx2+xey+xyeyx=-rsiny=rcos

Use these values in (1) we get

zr=ey(2x+y)-rsin+xey(x+1+y)rcoszr=rey(2x+y)sin+xcos(x+y+1)

This result is correct, but it is preferable to write the function as a function of just rand.

We use x=rcosandy=rsinto do so:

zr=rersin(2(rcos)+rsin)sin+rcoscos(rcos+rsin+1)zr=r2ersin(2sincos+sin2+cos2(rcos+rsin+1)zr=r2ersin(sin2+sin2+cos2(rcos+rsin+1)

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