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Use Theorem 12.33 to find the indicated derivatives in Exercises 27鈥30. Express your answers as functions of two variables.

ztwhenz=x2y3,x=tsins,andy=scost

Short Answer

Expert verified

The value iszt=s2tsin2scos2t(2scost+3tsint)

Step by step solution

01

Step 1. Given Information:

Given:

z=x2y3,x=tsinsandy=scost

We have to find the indicated derivatives and express your answers as functions of a single variable.

02

Step 2. Solution:

By Theorem 12.33, we have

zt=zxxt+zyyt---(1)

So first we find zx,xt,zyyt

So we have

zx=2xy3zy=3x2y2xt=sinsyt=-ssint

Use these values in (1) we get

role="math" localid="1649695474446" zt=2xy3sins+3x2y2(-ssint)zt=2xy3sins-3x2y2ssint

This result is correct, but it is preferable to write the function as a function of just s and t.

We use x=tsinsandy=scostto do so:

zt=2(tsins)(scost)3sins+3(tsins)2(scost)2ssintzt=2s3tsin2scos3t+3s2t2sin2scos2tsintzt=s2tsin2scos2t(2scost+3tsint)

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