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Chapter 12: Q 28. (page 916)

In Exercise, evaluate the given function at the specified points in the domain, and then find the domain and range of the function.

fx,y,z=x+y+zxyz,1,-2,6,-3,-2,4

Short Answer

Expert verified

f1,-2,6=-512f-3,-2,4=-124

Domain isR3-0,y,z,x,0,z,x,y,0and range is R.

Step by step solution

01

Step 1. Given information

Function isfx,y,z=x+y+zxyz

02

Step 2. Explanation

f(1,-2,6)=(1)+(-2)+(6)(1)(-2)(6)=5-12=-512f(-3,-2,4)=(-3)+(-2)+(4)(-3)(-2)(4)=-124=-124

For domain:

width="52">xyz=0

x= 0 or y = 0 or z = 0

These points are to be excluded from function's domain.

So, domain isR3-0,y,z,x,0,z,x,y,0range is R.

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