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Let $$u_{1}$$ and $$u_{2}$$ be two nonparallel unit vectors in $$R^{2}$$. If the function $$f(x, y)$$ is differentiable at a point $$(a, b)$$, explain why the tangent lines to the graph of $$f$$ at $$(a, b)$$ in the $$u_{1}$$ and $$u_{2}$$ directions are sufficient to determine the tangent plane to the surface.

Short Answer

Expert verified

If the function $$f(x, y)$$ is differentiable at a point $$(a, b)$$, then the tangent lines to the graph of $$f$$ at $$(a, b)$$ in the $$u_{1}$$ and $$u_{2}$$ directions are sufficient to determine the tangent plane to the surface since they lie in the same plane.

Step by step solution

01

Step 1. Given Information

  • Let $$u_{1}$$ and $$u_{2}$$ be two nonparallel unit vectors in $$R^{2}$$.
  • The function $$f(x, y)$$ is differentiable at a point $$(a, b)$$.
02

Step 2. Explanation

It is given that the function $$f(x, y)$$ is differentiable at a point $$(a, b)$$.

$$\implies$$ All the lines tangent to the surface defined by the function $$f$$ at the point $$(a,b)$$ lie in the same plane.

So, we can use any two distinct lines in that plane to determine the equation of the plane.

Here, $$u_{1}$$ and $$u_{2}$$ be two nonparallel unit vectors in $$R^{2}$$ that lie in the same plane.

Hence, if the function $$f(x, y)$$ is differentiable at a point $$(a, b)$$, then the tangent lines to the graph of $$f$$ at $$(a, b)$$ in the $$u_{1}$$ and $$u_{2}$$ directions are sufficient to determine the tangent plane to the surface.

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