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91Ó°ÊÓ

If a functionf(x,y,z) is differentiable at (a, b, c), explain

how to use the gradient∇f(a,b,c)to find the equation of

the hyperplane tangent to the graph of fat(a,b,c).

Short Answer

Expert verified

The equation of tangent plane to the surface w=f(x,y,z)at (a,b,c)is

w-f(a,b,c)=∇f(a,b,c)·⟨(x,y,z)-(a,b,c)⟩

Step by step solution

01

Given information

Let w=f(x,y,z)is a function of two variables defined on an open set containing the point (a,b,c)and

Let Δw=f(a+Δx,b+Δy,c+Δz)-f(a,b,c)

If fx(a,b,c),fy(a,b,c)and fz(a,b,c)exist, the functionf is said to be differentiable and

Δw=fx(a,b,c)Δx+fy(a,b,c)Δy+fz(a,b,c)Δz+ε1Δx+ε2Δy+ε3Δz……(1)

where ε1,ε2and ε3are functions of Δx,Δyand Δzand are zero when

(Δx,Δy)→(0,0)

02

The objective is to find the equation of the hyperplane tangent to the graph of f at (a,b,c)

Substitute Δx=x-a,Δy=y-b,Δz=z-cand Δw=f(x,y,z)-f(a,b,c)

in (1)and eliminate ε1Δx,ε2Δyand ε3Δzterms.

∆w=fx(a,b,c)∆x+fy(a,b,c)∆y+fz(a,b,c)∆z+ε1∆x+ε2∆y+ε3∆zf(x,y,z)-f(a,b,c)=fx(a,b,c)(x-a)+fy(a,b,c)(y-b)+fz(a,b,c)(z-c)w-f(a,b,c)=(fx(a,b,c),fy(a,b,c),fz(a,b,c))·((x-a),(x-b),(x-c))=∇f(a,b,c)·((x,y,z)-(a,b,c))

Hence, the equation of tangent plane to the surface w=f(x,y,z)at (a,b,c)is

w-f(a,b,c)=∇f(a,b,c)·⟨(x,y,z)-(a,b,c)⟩

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