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If a function f(x,y)is differentiable at (a,b), explain how to

use the gradient ∇f(a,b)to find the equation of the plane

tangent to the graph of fat (a,b).

Short Answer

Expert verified

The equation of tangent plane to the surface f(x,y)at (a,b)is:

z-f(a,b)=∇f(a,b)·⟨(x,y)-(a,b)⟩

Step by step solution

01

Given information

Let, f(x,y)is a function of two variables defined on an open set containing the point (a,b)

Let Δz=f(a+Δx,b+Δy)-f(a,b)

If both fx(a,b)and fy(a,b)exist, the function fis said to be differentiable and

Δz=fx(a,b)Δx+fy(a,b)Δy+ε1Δx+ε2Δy……(1).where ε1andε2 are functions of Δxand Δyand

both are zero when(Δx,Δy)→(0,0)

02

The objective is to find the equation of the plane tangent to the graph of f(x, y) at (a, b) 

Substitute Δx=x-a,Δy=y-band Δz=z-f(a,b)in (1)and eliminate ε1Δxand ε2Δyterms

z-f(a,b)=fx(a,b)(x-a)+fy(a,b)(y-b)⇒∆z=(fx(a,b),fy(a,b))·((x-a),(y-b))=∇f(a,b)·((x,y)-(a,b))

Hence, the equation of tangent plane to the surface f(x,y)at (a,b)is:

z-f(a,b)=∇f(a,b)·⟨(x,y)-(a,b)⟩

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