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Use the Squeeze Theorem to find each of the limits in Exercises. Explain exactly how the Squeeze Theorem applies in each case.

limx→0x2tan-11x

Short Answer

Expert verified

The limit of the equationlimx→0x2tan-11x is 0

Step by step solution

01

Step 1. Given Information:

limx→0x2tan-11x

02

Step 2. Applying Squeeze theorem on the limit:

By applying the Squeeze theorem;

Rangeoftan-11x"ortan-1x"is(-π2,π2)-π2<tan-11x<π2Nowmultiplyingx2onallside;-π2x2<x2tan-11x<π2x2Applyinglimitsonbothsideasx→0;limx→0-π2x2<limx→0x2tan-11x<limx→0π2x2-π2(0)<limx→0x2tan-11x<π2(0)0<limx→0x2tan-11x<0so,limx→0x2tan-11x=0

03

Step 3. Graph Representation: 

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