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Use the Squeeze Theorem to find each of the limits in Exercises. Explain exactly how the Squeeze Theorem applies in each case.

limx→1(x-1)cos1x-1

Short Answer

Expert verified

The limit of the equationlimx→1(x-1)cos1x-1is 0

Step by step solution

01

Step 1. Given Information:

limx→1(x-1)cos1x-1

02

Step 2. Applying Squeeze theorem on the limit:

By applying the Squeeze theorem;

Rangeofcos1x-1"orcosx"is[-1,1]-1≤cos1x-1≤1Nowmultiplying(x-1)onallside;-(x-1)≤(x-1)cos1x-1≤x-1-x+1≤(x-1)cos1x-1≤x-1Applyinglimitsonallsideasx→1;limx→1-x+1≤limx→1(x-1)cos1x-1≤limx→1x-1-1+1≤(1-1)cos11-1≤1-10≤0(cos0)≤00≤0≤0so,limx→1(x-1)cos1x-1=0
03

Step 3. Graph Representation: 

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