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Use the Squeeze Theorem to find the limits. Explain exactly how the Squeeze Theorem applies in each case.

limx→0ex-1sin1x

Short Answer

Expert verified

The limit of the given equation is 0.

Step by step solution

01

Step 1. Given information.

Consider the given question,
limx→0ex-1sin1x

02

Step 2. Apply squeeze theorem.

Range of sin1xor sinxis -1,1.

-1≤sin1x≤1

Multiply all the sides by ex-1,

-1ex-1≤sin1xex-1≤1ex-1-ex+1≤sin1xex-1≤ex-1

Applying limits on all the sides as x→0,

limx→0-ex+1≤limx→0sin1xex-1≤limx→0ex-1-e0+1≤limx→0sin1xex-1≤limx→0≤e0-1-1+1≤limx→0sin1xex-1≤1-10≤limx→0sin1xex-1≤0

Applying the Squeeze theorem,

=0

03

Step 3. Plot the graph.

Representing the graph, we get,

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