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Chapter 1: Q. 7 (page 151)

Use a calculator to find the sum of the first six terms of the sum from the previous problem, and compare this sum with your calculator鈥檚 best approximation of the number e.

Short Answer

Expert verified

The value of the first six-term of the expanded form of expression 1+1nnwith a limit n鈫�鈭�is the same as the value of e up to two decimal places.

Step by step solution

01

Step 1. Given information.

The given expanded form of expression as n鈫�鈭�is 1+1nn=1+11!+12!+13!+14!+15!+鈰�.

02

Step 2. Value of sum of the first six terms.

The sum of the first six-term of the expanded form of expression1+1nnwith a limitn鈫�鈭�is as follows.

1+11!+12!+13!+14!+15!=2.176

value of e is 2.718.

So the value of the first six-term of the expanded form of expression 1+1nnwith a limit n鈫�鈭�is the same as the value ofeup to two decimal places.

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