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Use the Extreme Value Theorem to show that each function f has both a maximum and a minimum value on [a, b]. Then use a graphing utility to approximate values M and m in [a, b] at which f has a maximum and a minimum, respectively. You may assume that these functions are continuous everywhere.

f(x)=3−2x2+x3,[a,b]=[0,2]

Short Answer

Expert verified

M=0,2m=1.33

Step by step solution

01

Step 1. Given information.

We have been given a function and an interval as:

f(x)=3−2x2+x3,[a,b]=[0,2]

We have to show that this function f has both a maximum and a minimum value on [a, b] using the Extreme Value Theorem.

Also, we have to find approximate values M and m in [a, b] at which f has a maximum and a minimum, respectively, using a graphing utility.

02

Step 2. Apply the Extreme Value Theorem 

limx→0 f(x)=limx→0 3−2x2+x3=3−202+03=3−0+0=3limx→2 f(x)=limx→2 3−2x2+x3=3−222+23=3−2(4)+8=3−8+8=3

03

Step 3. Draw the graph of the given function 

04

Step 4. Find M and m at which f has a maximum and a minimum 

The value of the function is maximum in the interval at x=0,2.

The value of the function is minimum in the interval at x=1.33.

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