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In Exercises 39–44, use Theorem 1.16 and left and right limits to determine whether each function f is continuous at its break point(s). For each discontinuity of f, describe the type of discontinuity and any one-sided discontinuity.

f(x)=x+1,ifx<13x-1,if1⩽x<2x+2,ifx⩾2.

Short Answer

Expert verified

Thefunctionisdiscontinuousatx=2onlyandthisisjumpdiscontinuityandthefunctionisrightcontinuousatx=2.

Step by step solution

01

Step 1. Given Information.

Given the function:

f(x)=x+1,ifx<13x-1,if1⩽x<2x+2,ifx⩾2anditsbreakpointswhicharex=1,2.

02

Step 2. Finding the limits at the break points.

Atx=1,LHL=limx→1-f(x)=limx→1-x+1=1+1=2.RHL=limx→1+f(x)=limx→1+3x-1=3-1=2.f(1)=3(1)-1=3-1=2.Since,LHL=RHL=f(1).Thismeansitiscontinuousatx=1.

Nowatx=2,LHL=limx→2-f(x)=limx→2-3x-1=6-1=5.RHL=limx→2+f(x)=limx→2+x+2=2+2=4.f(2)=x+2=2+2=4.So,RHL=f(2)≠LHL.

03

Step 3. Finding the type of discontinuity.

Since the function is discontinuous only at x=2,from Step 2.

Now we know RHL≠LHLandRHL=f(2)this means both left and righthand limit exists but they are not equal so this is jump discontinuity.

And also, RHL = f(2) this means this function is right continuous.

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