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Chapter 1: Q. 31 (page 120)

Sketch the graph of a function f described in Exercises 27鈥�32, if possible. If it is not possible, explain why not.

fhasaremovablediscontinuityatx=鈭�2andisrightcontinuousatx=鈭�2,andf(鈭�2)=0.

Short Answer

Expert verified

Function not possible.

Step by step solution

01

Step 1. Given Information.

Given:

f(-2)=0,fisrightcontinuousatx=-2,andithasaremovablediscontinuityatx=-2.

02

Step 2. Why function is not possible.

Now see that we are given that f has a removable discontinuity at x=-2this means the graph has a hole or a point at x=-2but just below in the second condition it is given that the absolute value of the function at x=-2is 0 which is a contradiction to it's own given condition.

Therefore, the function doesn't exist with these given conditions and so as the graph.

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Most popular questions from this chapter

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limh鈫�0(2+h)2-22h.

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State what it means for a function f to be right continuous at a point x = c, in terms of the delta鈥揺psilon definition of limit.

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