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A limit representing an instantaneous rate of change: After t seconds, a bowling ball dropped from 350feet has height h(t)=350-16t2,measured in feet.

Take the limit as h→0+of the formula you found for average rate of change in the previous problem. What does this limit represent in real-world terms?

Short Answer

Expert verified

Limit h→0+represents the initial time of observation of the average rate of change in height that is-96.

Step by step solution

01

Step 1. Given information.

The given function for the height ish(t)=350-16t2.

Given limit isrole="math" localid="1649778084185" h→0+

02

Step 2. The average rate of change in the height 

The average rate of change in the height of the bowling ball is as follows.

r=h(h+3)-h(3)(t+3)-3r=350-16(h+3)2-350-1632h+3-3r=350-16h2-96h-144-350+144hr=-16h2-96hhr=-16h-96

Take limit h→0+for The average rate of change in the height.

limh→0+r=limh→0+-16h-96=-16(0)-96=-96

Limit h→0+represents the initial time of observation of the average rate of change in height that is -96.

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