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Let f(x,y,z)be a continuous function of three variables, let localid="1650352548375" Ωyz={(y,z)|a≤y≤bandh1(y)≤z≤h2(y)}be a set of points in the yz-plane, and let localid="1650354983053" Ω={(x,y,z)|(y,z)∈Ωyzandg1(y,z)≤x≤g2(y,z)}be a set of points in 3-space. Find an iterated triple integral equal to the triple integral localid="1650353288865" ∭Ωf(x,y,z)dV. How would your answer change iflocalid="1650352747263" Ωyz={(y,z)|a≤z≤bandh1(z)≤x≤h2(z)}?

Short Answer

Expert verified

If in yz-plane,localid="1650353321170" Ωyz={(y,z)|a≤y≤bandh1(y)≤z≤h2(y)}, then the triple integral becomes,
localid="1650355042503" ∭Ωfx,y,zdv=∫ab∫h1zh2z∫g1x,yg2x,yfx,y,zdxdydz.

Because, localid="1650355058244" Ω={(x,y,z)|(y,z)∈Ωyzandg1(y,z)≤x≤g2(y,z)}.

Step by step solution

01

Step 1. Given information

Ω={(x,y,z)|(y,z)∈Ωyzandg1(y,z)≤x≤g2(y,z)}.

Ωyz={(y,z)|a≤y≤bandh1(y)≤z≤h2(y)}.

02

Step 2. Find an iterated integral which is equal to ∭Ωf(x, y,z) dV:

If in yz-plane Ωyz={(y,z)|a≤y≤bandh1(y)≤z≤h2(y)}, then the triple integral will become,

∭Ωfx,y,zdv=∫ab∫h1zh2z∫g1x,yg2x,yfx,y,zdxdydz.

Because,localid="1650355100648" Ω={(x,y,z)|(y,z)∈Ωyzandg1(y,z)≤x≤g2(y,z)}.

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