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Prove Theorem 13.10 (a). That is, show that if f(x,y)is an integrable function on the general region and cR, then

f(x,y)dA=f(x,y)dA

Short Answer

Expert verified

To prove this, write the double integral on left hand side as double Reimann sum.

Step by step solution

01

Given Information

It is given that

cf(x,y)dA=cf(x,y)dA

Region is subset of rectangular region defined by

role="math" localid="1653943372914" R={(x,y)axbandcyd}, that is,Randc is real number.

02

Simplify using property

We know property of double integral

f(x,y)dA=RF(x,y)dA

and

localid="1653944299120" F(x,y)=(x,y),if(x,y)and 0,if(x,y)

write the double integral on left hand side as double Reimann sum.

RcF(x,y)dA=lim0i=1mj=1ncFxi*,yj*Aand

=(x)2+(y)2

Simplify RHS

RcF(x,y)dA=clim0i=1mj=1nFxi*,yj*A

=cRF(x,y)dA

From same property cf(x,y)dA=cf(x,y)dA

Equation is true.

03

Simplification

Changing order of sum

RcF(x,y)dA=lim0j=1ni=1mcFxi*,yj*A

RcF(x,y)dA=clim0j=1ni=1mFxi*,yj*A

=cRF(x,y)dA

From property stated above

cf(x,y)dA=cf(x,y)dA

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