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Let f(x,y)be an integrable function on the rectangle R={(x,y)axbandcyd}and cyd}, and let . Use the definition of the double integral to prove that

Rf(x,y)dA=Rf(x,y)dA.

Short Answer

Expert verified

To prove this, write the double integral on left hand side as double Reimann sum.

Step by step solution

01

Given Information

It is given that Rf(x,y)dA=Rf(x,y)dAand R={(x,y)axbandcyd}

is real number.

02

Proof

Rf(x,y)dA=lim0i=1mj=1nfxi*,yj*A

and =(x)2+(y)2

Rf(x,y)dA=lim0i=1mj=1nfxi*,yj*A

=Rf(x,y)dA

The equation is true.

Changing order of sum

Rf(x,y)dA=lim0j=1ni=1mfxi*,yj*A

Rf(x,y)dA=lim0j=1ni=1mfxi*,yj*A

=Rf(x,y)dA

Equation is true.

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