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91Ó°ÊÓ

The region bounded above by the plane with equation z=x and bounded below by the paraboloid with equationz=x2+y2.

Short Answer

Expert verified

Volume of solid isV=Ï€32units

Step by step solution

01

Given Information

The equations arez=xandz=x2+y2.

02

Simplification

The relationship between rectangular and cylindrical coordinates are:

r=x2+y2,tanθ=yx,z=z

x=rcosθ,y=rsinθ,z=z

03

Evaluation of Limits

The rectangular coordinates are z=xand z=x2+y2

The cylindrical coordinates are z=rcosθand z=r2

The cartesian limits are x2+y2≤z≤x

x=rcosθ

Hence, z=x⇒z=rcosθ

And r2=x2+y2

Hence, z=x2+y2⇒z=r2

It implies r2≤z≤rcosθ

Simplifying

x2+y2=x

⇒r2=rcosθ

Simplifying role="math" localid="1652376534758" r=0,r=cosθ⇒0≤r≤cosθ

The cylindrical limits are:

r2≤z≤rcosθ,0≤r≤cosθ&-π/2≤θ≤π/2

04

Evaluation of Volume

Required volume is given by

V=∫θ=-π/2π/2∫r=0cosθ∫z=r2rcosθrdzdrdθ

=∫θ=-π/2π/2∫r=0cosθr(z)z=r2rcosθdrdθ

=∫θ=-π/2π/2∫r=0cosθrrcosθ-r2drdθ

=∫θ=-π/2π/2cosθr33r=0r=cosθdθ-∫θ=-π/2π/2r44r=0r=cosθdθ

V=∫θ=-π/2π/213cos4θdθ-∫θ=-π/2π/214cos4θdθ

Further simplification gives

V=23∫θ=0π/2cos4θdθ-14·2∫θ=0π/2cos4θdθ

V=23×34×12×π2-12×34×12×π2

V=4Ï€32-3Ï€32

V=Ï€32units

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