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Each of the integrals or integral expressions in Exercises 39-46 represents the volume of a solid in 3.Use polar coordinates to describe the solid, and evaluate the expressions.

-/45/40(2/2)+sinrdrd

Short Answer

Expert verified

The value of integral is

-/45/40(2/2)+sinrdrd=34(+1)

Step by step solution

01

Given information

The expression is

I=-/45/40(2/2)+sinrdrd
02

Calculation

Here, r=0,r=(2/2)+sinand=-/4,=5/4

Integrate with respect to rfirst,

I=-/45/4r220(2/2)+sindxndx=xn+1n+1+C

Put the limits

I=-/45/4{(2/2)+sin}2-02dI=-/45/412+2sin+sin22dI=-/45/412+2sin+12(1-cos2)2d

Now integrate with respect to

I=2-2cos+12-12sin22-/43/4

I=-2cos-14sin2-/45/42I=54-2cos54-14sin52--4-2cos-4-14sin-22

I=54-2-12-14--4-212+142I=54+1-14--4-1+142I=34(+1)

Thus, the value of integral is

localid="1651500227368" -/45/40(2/2)+sinrdrd=34(+1)

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