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Each of the integrals or integral expressions in Exercises 39-46 represents the volume of a solid in 3. Use polar coordinates to describe the solid, and evaluate the expressions.

00RR2r-r3drd

Short Answer

Expert verified

The value of integral is0z0R2r-r3drd=R44

Step by step solution

01

Given information

The expression is I=00RR2r-r3drd

02

Calculation

The objective of this problem is to use polar coordinates to describe the solid and evaluate the integral expression.

I=00RR2r-r3drd

Here, r=0,r=R and =0,=

Integrate with respect to r first,

I=0R2r22-r440Rdxndx=xn+1n+1+C

Substitute the limits

I=0R42-R44d

I=int0R44d

Now integrate with respect to

I=R44[]0I=R44

Thus, the value of integral is

0z0R2r-r3drd=R44

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