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91Ó°ÊÓ

Evaluate the iterated integral :

∫01 ∫03−3y ∫06y xydzdxdy

Short Answer

Expert verified

9

Step by step solution

01

Step 1. Given information.

Given integral is :

∫01 ∫03−3y ∫06y xydzdxdy

We have to evaluate it.

02

Step 2. Evaluate.

Given ∫01 ∫03−3y ∫06y xydzdxdy

=∫01 ∫03−3y ∫06y xydzdxdy=∫01 ∫03−3y xy∫06y dzdxdy=∫01 ∫03−3y xy(z)06ydxdy=∫01 ∫03−3y xy(6y)dxdy=∫01 ∫03−3y (6x)dxdy

03

Step 3. Integrate with respect to z.

Integrate with respect to z

=∫01 ∫03−3y 6xdxdy=∫01 6x2203−3ydy=∫01 3x203−3ydy=∫01 3(3−3y)2dy=∫01 39−18y+9y2dy=27∫01 dy−54∫01 ydy+27∫01 y2dy=27(y)01−54y2201+27y3301=27−27+9=9

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