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Using polar coordinates to evaluate iterated integrals: Evaluate the given iterated integrals by converting them to polar coordinates. Include a sketch of the region.

∫-33∫-9-x29-x2x+2yx2+y2dydx

Short Answer

Expert verified

∫-33∫-9-x29-x2x+2yx2+y2dydx=0

Step by step solution

01

Step !: Draw the region

From the limits of integration, the region is shown below,

02

Convert into polar form

By using the below substitution,

x=rcosθy=rsinθx2+y2=r2dxdy=rdrdθ

The equivalent polar integral of the given integral is,

∫-33∫-9-x29-x2x+2yx2+y2dydx⇒∫02π∫03(cosθ+2sinθ)drdθ

03

Calculate the integral

I=∫02π∫03(cosθ+2sinθ)drdθI=∫02π(cosθ+2sinθ)dθ∫03rdrI=sinθ-2cosθ02π∫03rdrI=-2-(-2)∫03rdrI=(-2+2)∫03rdrI=0

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