91Ó°ÊÓ

We have given that :-

$\frac{d}{dx}\left(x^{-4}\right)=-4x^{-5}$.

We have to prove this derivative by using implicit differentiation and the following derivative :-

$\frac{d}{dx}\left(x^4\right)=4x^3$.

We have to find the derivative of $x^{-4}$.

Let :-

role="math" localid="1648649200808" $y=x^{-4}$.

We can write it as :-

role="math" localid="1648649223011" $y{x}^4=1$.

Then by using implicit differentiation and product rule, we have :-

role="math" localid="1648649255089" $y\left[\frac{d}{dx}\left(x^4\right)\right]+x^4\frac{dy}{dx}=0$

We have given that :-

$\frac{d}{dx}\left(x^4\right)=4x^3$. By using this we have :-

role="math" localid="1648649281598" $$\begin{gathered} y\left(4x^3\right)+x^4\frac{dy}{dx}=0 \\ ⇒4x^{3}y+x^4\frac{dy}{dx}=0 \\ ⇒x^4\frac{dy}{dx}=-4x^{3}y \\ ⇒\frac{dy}{dx}=-\frac{4x^{3}y}{x^4} \\ ⇒\frac{dy}{dx}=-\frac{4y}{x} \end{gathered}$$

Put the value $y=x^{-4}$, then we have :-

role="math" localid="1648649306231" $$\begin{gathered} \frac{d}{dx}\left(x^{-4}\right)=-\frac{4x^{-4}}{x} \\ ⇒\frac{d}{dx}\left(x^{-4}\right)=-4x^{-4}{x}^{-1} \\ ⇒\frac{d}{dx}\left(x^{-4}\right)=-4x^{-5} \end{gathered}$$

This is the required value.

Hence proved.