Q. 39 For each function f and value x=... [FREE SOLUTION]

Chapter 2: Q. 39 (page 166)

For each function f and value $x = c$ in Exercises 35鈥�44, use a sequence of approximations to estimate $f' (c)$ . Illustrate your work with an appropriate sequence of graphs of secant lines.
$f (x) = \ln (x^{2} + 1), c = 0$

Short Answer

Expert verified

The value is $f' (0) = 0$ .

Step by step solution

Step 1. Given Information

We are given a function $f (x) = \ln (x^{2} + 1), c = 0$ and using a sequence of approximations we have to estimate $f' (c)$ .

Step 2. Using a sequence of approximations

$h = 1, \frac{f (1) - f (0)}{1 - 0} = \frac{\ln ({(1)}^{2} + 1) - \ln ({(0)}^{2} + 1)}{1} = \frac{\ln (2) - 0}{1} = \ln (2) = 0.6931 h = 0.5, \frac{f (0.5) - f (0)}{0.5 - 0} = \frac{\ln ({(0.5)}^{2} + 1) - \ln ({(0)}^{2} + 1)}{0.5} = \frac{\ln (1.25) - 0}{0.5} = 0.4462 h = 0.1, \frac{f (0.1) - f (0)}{0.1 - 0} = \frac{\ln ({(0.1)}^{2} + 1) - \ln ({(0)}^{2} + 1)}{0.1} = \frac{\ln (1.01) - 0}{0.1} = 0.0995 h = 0.01, \frac{f (0.01) - f (0)}{0.01 - 0} = \frac{\ln ({(0.01)}^{2} + 1) - \ln ({(0)}^{2} + 1)}{0.01} = \frac{\ln (1.0001) - 0}{0.01} = 0.009$

We might guess that the slope of the tangent line is $f' (0) = 0$ .

The graph of the function is

Step 3. Graphs of secant lines

When $c = 0, c + h = 1$ with $h = 1$ we have $f (0) =, f (1) = \ln (2)$ the secant line can be drawn as follows:

When $c = 0, c + h = 0.5$ with $h = 0.5$ we have $f (0) = 0, f (0.5) = 0.2231$ the secant line can be drawn as follows:

When $c = 0, c + h = 0.1$ with $h = 0.1$ we have $f (0) = 0, f (0.1) = 0.0099$ the secant line can be drawn as follows:

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91影视

For each function f and value $x = c$ in Exercises 35鈥�44, use a sequence of approximations to estimate $f' (c)$ . Illustrate your work with an appropriate sequence of graphs of secant lines.
$f (x) = \ln (x^{2} + 1), c = 0$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Using a sequence of approximations

Step 3. Graphs of secant lines

One App. One Place for Learning.

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91影视

For each function f and value x=cin Exercises 35鈥�44, use a sequence of approximations to estimate f'(c). Illustrate your work with an appropriate sequence of graphs of secant lines.f(x)=lnx2+1,c=0

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Using a sequence of approximations

Step 3. Graphs of secant lines

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Logic and Functions

Calculus

Pure Maths

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Statistics

Study anywhere. Anytime. Across all devices.

For each function f and value $x = c$ in Exercises 35鈥�44, use a sequence of approximations to estimate $f' (c)$ . Illustrate your work with an appropriate sequence of graphs of secant lines.
$f (x) = \ln (x^{2} + 1), c = 0$