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Find a function f that has the given derivative f' and value f(c).

f'x=11+4x2,f0=1

Short Answer

Expert verified

The anti derivative isfx=12tan-12x+1

Step by step solution

01

Step 1:Given information

The given expression isf'x=11+4x2,f0=1

02

Step 2:Simplification

Given f'x=11+4x2

We will use an intelligent guess-and-check method to find f

width="198" height="44" role="math">⇒ddxtan-12x=21+2x2

. We need only divide our guess by that constant. Try the function f(x)=12tan-12x

⇒ddx12tan-12x=12.21+4x2

=11+4x2

Hence,

fx=12tan-12x+c

Now,

f0=1⇒1=12tan-10+c⇒c=1

Therefore,

The antiderivative isfx=12tan-12x+1

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