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Use (a) the h→0 definition of the derivative and then (b) the z→c definition of the derivative to find f'(c) for each function f and value x = c.

f(x)=x2−3xx+1,x=0

Short Answer

Expert verified

(a) f'(c)=-3

(b)f'(c)=-3

Step by step solution

01

Part (a) Step 1. Given information.

Given function is f(x)=x2−3xx+1

We have to findf'(c)atx=0

02

Part (a) Step 2. Find the f'(c)

We have to find the derivative of the function using h→0 definition,

Therefore,

limh→0 f(0+h)−f(0)h=limh→0 (0+h)2−3(0+h)0+h+1−0−00+1h=limh→0 h2−3hh+1h=limh→0 h(h−3)h(h+1)=limh→0 h(h−3)h(h+1)=limh→0 h−3h+1=−3

03

Part (b) Step 1. Find f'(c)

Find the derivate of the function using x→0definition,

limx→0 f(x)−f(0)x−0=limx→0 x2−3xx+1−0−00+1x=limx→0 x(x−3)x(x+1)=limx→0 x−3x+1=−3

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