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If f is a differentiable function, then the values x=cat which the sign of the second derivative f''xchanges are the locations of the inflection points of f. Use this information to find the inflection points of the functionfx=sinx. Illustrate your answer on a graph ofy=sinx.

Short Answer

Expert verified

The local extrema of the given function is at x=n. The graph of the given function is given below,

Step by step solution

01

Step 1. Given information.

Consider the given question,

The function isfx=sinx.

02

Step 2. Find the derivatives of the given function.

Derivative of the given function,

f'x=cosx

For critical points, put f'x=0. Then,

0=cosxx=...,-32,-2,0,2,32,...x=2n+12

Where, n is an integer.

The second derivate of the given function,

f''x=-sinx

When (2n-1)<x<2n,n=0,1,2,f''x=-sinx>0.

When 2n<x<2n+1,n=0,1,2,...f''x=-sinx<0.

Therefore, the required graph isy=sinx.

03

Step 3. Plot the function.

On plotting the function is given below,

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