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Chapter 2: Q 20. (page 238)

Find the derivatives of the function:f(x)=x3secx.

Short Answer

Expert verified

The derivative of f(x)=x3sec(x)isx2{3secx+xtanxsecx}.

Step by step solution

01

Given information  

The given expression isf(x)=x3secx.

02

Simplification    

f'(x)=ddx(x3secx)=secxddx(x3)+x3ddxsecx=3x2脳1cosx+x3sinxcos2x=x2{3secx+xtanxsecx}.Hence,f'(x)=x2{3secx+xtanxsecx}.

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