/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 20 Find the derivatives of each of ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the derivatives of each of the functions in Exercises 17–50. In some cases it may be convenient to do some preliminary algebra.

f(x)=tan23x+1.

Short Answer

Expert verified

Thevalueofthederivativeis:6tan(3x+1)sec2(3x+1).

Step by step solution

01

Step 1. Given Information.

f(x)=tan23x+1.

02

Step 2. General formulas for finding derivatives. 

ddxxn=nxn-1,ddxsinx=cosx,ddxcosx=-sinx,ddxtanx=sec2x,ddx(secx)=secxtanx,ddx(cscx)=-cscxcotx,ddx(cotx)=-csc2x,Productrule:ddx(uv)=udvdx+vdudx,Quotientrule:ddxuv=vdudx-udvdxv2,Chainrule:ddxfog(x)=ddxf(g(x))×ddx(g(x).

03

Step 3. Solving derivative using above formulas.

f(x)=tan2(3x+1),Differentiatingusingchainruleweget,ddx(f(x))=2tan(3x+1)ddx(tan(3x+1))=2tan(3x+1)sec2(3x+1)ddx(3x+1)=2tan(3x+1)sec2(3x+1)(3)=6tan(3x+1)sec2(3x+1).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.