91Ó°ÊÓ

Given functions are the following.

$$\begin{gathered} k\left(x\right)={\left(x^2+1\right)}^3 \\ k\left(x\right)=\sqrt{1+{\left(x-2\right)}^2} \\ k\left(x\right)=\sqrt{\frac{1}{3x+1}} \\ k\left(x\right)=\frac{1}{\sqrt{3x+1}} \end{gathered}$$

Consider $f\left(x\right)=x^3,g\left(x\right)=\left(x+1\right),\&h\left(x\right)=x^2.$

Composition of functions.

$$\begin{gathered} f∘g∘h=f\left(g\right(h\left(x\right)\left)\right) \\ f∘g∘h==f\left(g\right(x^2\left)\right) \\ f∘g∘h==f(x^2+1) \\ f∘g∘h={(x^2+1)}^3 \\ \left(f∘g∘h\right)\left(x\right)=k\left(x\right) \end{gathered}$$

Consider$f\left(x\right)=\sqrt{x},g\left(x\right)=\left(1+x^2\right),\&h\left(x\right)=x-2.$

Composition of functions.

role="math" localid="1648711630588" $$\begin{gathered} \left(f∘g∘h\right)\left(x\right)=f\left(g\right(h\left(x\right)\left)\right) \\ \left(f∘g∘h\right)\left(x\right)=f\left(g\right(x-2\left)\right) \\ \left(f∘g∘h\right)\left(x\right)=f(1+{\left(x-2\right)}^2) \\ \left(f∘g∘h\right)\left(x\right)=\sqrt{1+{\left(x-2\right)}^2} \\ \left(f∘g∘h\right)\left(x\right)=k\left(x\right) \end{gathered}$$

Consider$f\left(x\right)=\sqrt{x},g\left(x\right)=\frac{1}{x+1},\&h\left(x\right)=3x.$

Composition of functions.

$$\begin{gathered} \left(f∘g∘h\right)\left(x\right)=f\left(g\right(h\left(x\right)\left)\right) \\ \left(f∘g∘h\right)\left(x\right)=f\left(g\right(3x\left)\right) \\ \left(f∘g∘h\right)\left(x\right)=f\left(\frac{1}{3x+1}\right) \\ \left(f∘g∘h\right)\left(x\right)=\sqrt{\frac{1}{3x+1}} \\ \left(f∘g∘h\right)\left(x\right)=k\left(x\right) \end{gathered}$$

Consider$f\left(x\right)=\frac{1}{x},g\left(x\right)=\sqrt{x+1},\&h\left(x\right)=3x.$

Composition of functions.

$$\begin{gathered} \left(f∘g∘h\right)\left(x\right)=f\left(g\right(h\left(x\right)\left)\right) \\ \left(f∘g∘h\right)\left(x\right)=f\left(g\right(3x\left)\right) \\ \left(f∘g∘h\right)\left(x\right)=f\left(\sqrt{3x+1}\right) \\ \left(f∘g∘h\right)\left(x\right)=\frac{1}{\sqrt{3x+1}} \\ \left(f∘g∘h\right)\left(x\right)=k\left(x\right). \end{gathered}$$