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Supposef1=3,limx→1-fx=3,limx→1+fx=3,role="math" localid="1648483351627" limx→0-f1+h-f1h=2,limx→0+f1+h-f1h=0

(a) Is fcontinuous and/or differentiable at x=0? What

about from the left or right?

(b) Sketch a possible graph of f.

Short Answer

Expert verified

The function fis continuous but not differentiable at x=1.

The possible graph can be as follow:

Step by step solution

01

Step 1. Given information

It is given thatf1=3,limx→1-fx=3,limx→1+fx=3,limh→0-f1+h-f1h=2,limh→0+f1+h-f1h=0

02

Step 2. Check continuity and differentiability at x=1

Since f1=3, limx→1-fx=3, limx→1+fx=3, therefore the function is continuous at x=1.

limh→0-f1+h-f1h=2and limh→0+f1+h-f1h=0

Left hand derivatives and Right hand derivatives are not equal, So the function is not differentiable atx=1.

03

Step 3. Draw the possible graph of f.

The possible function will be

fx=3,ifx≥02x+1,ifx<0

So, the graph will be

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