/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 69 For each function f and interval... [FREE SOLUTION] | 91Ó°ÊÓ

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For each function f and interval [a, b] given in Exercises 68–73, find a real number c ∈ (a, b) such that f(c) is the average value of f on [a, b]. Then use a graph of f to verify that your answer is reasonable.

f(x)=2x2+1,[a,b]=[−1,2]

Short Answer

Expert verified

The real number is 1and the average value is localid="1648721084595" 3and it is verified from the graph.

Step by step solution

01

Step 1. Given Information.

The given function and the interval isf(x)=2x2+1,[a,b]=[−1,2].

02

Step 2. Finding a real number c ∈ (a, b).

To find a real number c ∈ (a, b) such that f(c) is the average value of f on [a, b]. We will use the average value formula: 1b-a∫abf(x)dx.

1b-a∫abf(x)dx=12--1∫-122x2+1dx=132x33+x-12=132233+2-2-133+(-1)=13163+2+53=1316+6+53=13273=3

Thus, the average value is3.

Now,

f(c)=32c2+1=32c2=2c2=1c=±1

The real number will be1,1∈-1,2.

03

Step 3. Verification. 

By using the graphing utility, the graph off is

From the graph, we can depict that f(c)=3.Thus, the real number is1,1∈-1,2. Hence, the answer is right.

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