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The proof of the latter part of the Second Fundamental Theorem of Calculus in the reading covered only the case h→0+. Rewrite this proof in your own words, and then write a proof of what happens as h→0-.

Short Answer

Expert verified

The Second Fundamental Theorem states that if fis continuous on a,bthen role="math" localid="1648741945639" Fx=∫0xftdtfor all x∈a,b, then

Fis continuous on a,band differentiable on a,band Fis an antiderivative of f, i.e.,F'x=fx.

Step by step solution

01

Step 1. Given information

We have to proof the latter part of the Second Fundamental Theorem of Calculus the case whenh→0+.

02

Step 2. Proof of the given question

It is required to prove that Fis an antiderivative of f, i.e. F'x=fx.

Considering the right derivative, his positive.

So,

Fx=∫0xftdt

Finding its derivative with respect to x,

F'x=limh→0+Fx+h-Fxh=limh→0+∫ax+hftdt-∫axftdth=limh→0+∫ax+hftdt+∫xaftdth=limh→0+∫xx+hftdth

The Mean Value Theorem is,

fc=∫abfxdxb-a

Applying it to limh→0+∫xx+hftdth

limh→0+∫xx+hftdth=limh→0+fc

This means that there is some con x,x+h.

In the limit as hgoes to 0+, cgets squeezed down to x.

Since fxis continuous,

limh→∞fc=limc→xfc=fx

Therefore,F'x=limh→0+Fx+h-Fxh=fxis proved.

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