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91Ó°ÊÓ

Use the Fundamental Theorem of Calculus to find the exact

values of each of the definite integrals in Exercises 19–64. Use

a graph to check your answer.

∫06|(x-1)(x-4)|dx

Short Answer

Expert verified

The value of integral is 15and the plot is

Step by step solution

01

Step 1. Given information

An expression is given as∫06|(x-1)(x-4)|dx

02

Step 2. Evaluating integral

We have to change the integral as

f(x)=(x-1)(x-4)0≤x≤1-(x-1)(x-4)1≤x≤4(x-1)(x-4)4≤x≤6

Now evaluate the integral,

∫06|(x-1)(x-4)|dx=∫01(x-1)(x-4)dx+∫14-(x-1)(x-4)dx+∫46(x-1)(x-4)dx=∫01x2-5x+4dx-∫14x2-5x+4dx+∫46x2-5x+4dx=x33-52x2+4x01-x33-52x2+4x14+x33-52x2+4x46=133-52(1)2+4(1)-0-433-52(4)2+4(4)-133-52(1)2+4(1)+633-52(6)2+4(6)-433-52(4)2+4(4)=116--92+263=116+92+263=906=15

And the plot is

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