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For each function f and interval[a, b] in Exercises 56–67, use definite integrals and the Fundamental Theorem of Calculus to find the exact average value of f from x = a to x = b. Then use a graph of f to verify that your answer is reasonable.

f(x)=x-1,-1,3

Short Answer

Expert verified

The exact average value of f is 0and it is verified from the graph of f.

The graph is

Step by step solution

01

Step 1. Given Information.

The given function and interval isf(x)=x-1,-1,3.

02

Step 2. Finding the exact average value.

To find the exact average value of f from x=atox=b,we will use the formula: 1b-a∫abf(x)dx.

Thus,

1b-a∫abf(x)dx=13-(-1)∫-13(x-1)dx=14x22-x-13=14322-3--122-(-1)=1492-3-12-1=149-6-1-22=140=0

03

Step 3. Verification.

The graph of f is

From the graph, we can depict that the average value is 0.Thus, the answer is right.

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Most popular questions from this chapter

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Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: The absolute area between the graph of f and the x-axis on [a, b] is equal to|∫abf(x)dx|.

(b) True or False: The area of the region between f(x) = x − 4 and g(x) = -x2on the interval [−3, 3] is negative.

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(g) True or False: The average value of f on [1, 5] is equal to the average of the average value of f on [1, 2] and the average value of f on [2, 5].

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