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91Ó°ÊÓ

Use the Fundamental Theorem of Calculus to find the exact

values of each of the definite integrals in Exercises 19–64. Use

a graph to check your answer. (Hint: The integrands that involve

absolute values will have to be considered piecewise.)

∫π4π2x(csc2(x2))dx

Short Answer

Expert verified

∫π4π2x(csc2(x2))dx=12cot(π216)-12cot(π24).

Step by step solution

01

Step 1. Given information.

A definite integral is given as∫π4π2x(csc2(x2))dx.

02

Step 2. Using the Fundamental theorem of Calculus.

Let

f(x)=-cotxg(x)=x2

such that

f'(x)=csc2xg'(x)=2xf'(g(x))=csc2(x2)

Now we get

localid="1648766755631" ∫π4π2x(csc2(x2))dx=12∫π4π22x(csc2(x2))dx=-12[cot(x2)]π4π2[f'(g(x))g'(x)dx=f(g(x))]=-12[cot(π2)2-cot(π4)2]=12cot(π216)-12cot(π24)

The exact value of the given definite integral is12cot(Ï€216)-12cot(Ï€24).

03

Step 3. The graph to verify the answer is

The solution is area under graph which is

a≈1.330759≈12[cot(π216)-cot(π24)]

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