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Indefinite integrals of combinations: Fill in the blanks to complete the integration rules that follow. You may assume that fand gare continuous functions and thatk is any real number.
∫f'(x)g(x)−f(x)g'(x)(g(x))2dx=____

Short Answer

Expert verified

∫f'(x)g(x)−f(x)g'(x)(g(x))2dx=f(x)g(x)+C

Step by step solution

01

Step 1. Given Information

∫f'(x)g(x)−f(x)g'(x)(g(x))2dx=____

02

Step 2. Solving the expression

As quotient rule of derivative isddxuv=u'v-uv'v2

So,

role="math" localid="1649792911630" width="242" height="47">ddxf(x)g(x)=f(x)'g(x)-f(x)g'(x)(g(x))2
role="math" localid="1649792902040" width="258" height="47">df(x)g(x)=f(x)'g(x)-f(x)g'(x)(g(x))2dx

Integrating both sides

∫df(x)g(x)=∫f(x)'g(x)-f(x)g'(x)(g(x))2dx
∫f(x)'g(x)−f(x)g'(x)(g(x))2dx=f(x)g(x)+C

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