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Use the Second Fundamental Theorem of Calculus, if needed, to calculate each of the derivatives given below.

ddxx20sinxtdt

Short Answer

Expert verified

Ans: ddxx20sinxtdt=2xsinxcosx+x2cos2x2sinxx2sinxsinx

Step by step solution

01

Step 1. Given information.

given expression,

ddxx20sinxtdt

02

Step 2. The objective is to calculate the derivative. 

Now, if fis continuous on role="math" localid="1648716835455" [a,b]then for allrole="math" localid="1648716841853" x[a,b],

ddxau(x)f(t)dt=f(u(x))u(x)

So,

f(u(t))=sintf(u(x))=sinxu(x)=cosxf(u(x))u(x)=sinxcosx

03

Step 3. The derivate expression can be written as, 

ddxx20sinxtdt=ddxx2sinxcosx=2xsinxcosx+x2ddxsinxcosx=2xsinxcosx+x2cosx2sinxcosx+sinx(sinx)=2xsinxcosx+x2cos2x2sinxx2sinxsinx

Therefore, the answer is 2xsinxcosx+x2cos2x2sinxx2sinxsinx

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