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Combining derivatives and integrals: Simplify each of the following as much as possible:

ddxx3sin3tdt

Short Answer

Expert verified

The solution isddxx3sin3tdt=(-34[sinx]+14[sin3x])

Step by step solution

01

Step 1. Given information

Integral:ddxx3sin3tdt

02

Step 2. Calculation

The given integration is ddxx3sin3tdt

ddxx3sin3tdt

Using sin3x=34sinx-14sin3x

=ddxx3(34sint-14sin3t)dt=ddx(34x3(sint)dt-14x3(sin3t)dt)Usingsinxdx=-cosx+C=ddx(34[-cost]x3-14[-13cos3t]x3) =ddx(-34[cos3-cosx]+112[cos9-cos3x])=(-34ddx[cos3-cosx]+112ddx[cos9-cos3x]usingddxcosx=-sinx=(-34[sinx]+112[3sin3x])=(34[sinx]+14[sin3x])

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