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Use the Second Fundamental Theorem of Calculus, if needed, to calculate each of the derivatives given below.

d2dx223xt2+1dt

Short Answer

Expert verified

Ans: d2dx223xt2+1dt=54x

Step by step solution

01

Step 1. Given information.

given expression,

d2dx223xt2+1dt

02

Step 2.  The objective is to calculate the derivative.

Now, iffis continuous on[a,b]then for allx[a,b],

ddxau(x)f(t)dt=f(u(x))u(x)

So,

f(u(t))=(3t)2+1f(u(x))=(3x)2+1u(x)=3f(u(x))u(x)=33x2+1

03

Step 3. The derivate expression can be written as,

d2dx223xt2+1dt=ddxddx23xt2+1dt=ddx3(3x)2+1=3ddx(3x)2+1=3ddx9x2+1=3(18x)+0=54x

Therefore, the answer is54x

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