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In Exercises 39–44, write out the sigma notation for the Riemann sum described in such a way that the only letter which appears in the general term of the sum is k. Don’t calculate the value of the sum; just write it down in sigma notation.

fx=lnx,a,b=2,5,leftsum,n=100

Short Answer

Expert verified

The left sum is=0.03∑k=1100ln2+0.03k-1

Step by step solution

01

Step 1. Given Information

The given function isfx=lnx,a,b=2,5,leftsum,n=100

02

Step 2. Finding ∆x and xk

∆x=b-an=5-2100=3100=0.03

xk=a+k∆x=2+0.03kxk-1=a+k-1∆x=2+0.03k-1

03

Step 3. Finding Reimann Sum

We have fx=lnxthen fxk-1=lnxk-1

Now,∑k=1100fxk-1∆x=∑k=1100ln2+0.03k-10.03=0.03∑k=1100ln2+0.03k-1

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