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91Ó°ÊÓ

Combining derivatives and integrals: Simplify each of the following as much as possible:

∫-2xddx(ln(x2+1))dx

Short Answer

Expert verified

The solution is∫-2xddx(ln(x2+1))dx=[x2+15].

Step by step solution

01

Step 1. Given information

Simplify:∫-2xddx(ln(x2+1))dx

02

Step 2. Calculation

The given equation is:

∫-2xddx(ln(x2+1))dx

ddxlnx=1x& Chain rule

∫-2xddx(ln(x2+1))dx=∫-2x(1(x2+1)dxddx(x2+1))dx∫-2xddx(ln(x2+1))dx=∫-2x(2x(x2+1))dxLet(x2+1)=t

Differentiate both sides with respect to 't'

ddt(x2+1)=dtdt2xdx=dt

Also when

x=-2thent=5&whenx=xthent=(x2+1)

∫-2xddx(ln(x2+1))dx=∫5x2+1(1t)dtUsing∫1xdx=lnx+C∫-2xddx(ln(x2+1))dx=[lnt]5x2+1 ∫-2xddx(ln(x2+1))dx=[lnx2+1-ln5]∫-2xddx(ln(x2+1))dx=[lnx2+15]

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