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Use integration formulas to solve each integral in Exercises 21–62. You may have to use algebra, educated guess-and-check, and/or recognize an integrand as the result of a product, quotient, or chain rule calculation. Check each of your answers by differentiating.

∫4ex-32dx

Short Answer

Expert verified

The solution of the integral is2e2x-6+C.

Step by step solution

01

Step 1. Given Information.

The given integral is∫4ex-32dx.

02

Step 2. Solve. 

By solving the integral we get,

∫4ex-32dx=∫4e2x-6dx=4∫e2x-6dxUse∫exdx=ex+C=412e2x-6+C=2e2x-6+C

03

Step 3. Verification. 

To verify the answer we differentiate 2e2x-6+Cit.

On differentiating we get,

2e2x-6+C=ddx2e2x-6+ddxC=4e2x-6+0=4e2x-6

Hence proved.

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