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Are definite integrals the 鈥渋nverse鈥 of differentiation? In other words, does one undo the other? Simplify each of the following to answer this question:

(a)abf'(x)dx(b)ddxabf(x)dx

Short Answer

Expert verified

Part aThe simplified expression for abf'(x)dxis, fb-fa.

PartbThe simplified expression forrole="math" localid="1648811812391" ddxabf(x)dxis,0.

Step by step solution

01

Part a Step 1. Given information

abf'(x)dx.

02

Part a Step 2. The objective is, we need to simplify the given expression.

ddxf(x)=f'(x)

So,

f'(x)dx=[f(x)]ab=fb-fa

03

Part b Step 1. Given information

ddxabf(x)dx.

04

Part b Step 2. The objective is, we need to simplify the given expression.

Fx=fx [Fxis an antiderivative of fx]

So,

ddxabf(x)dx=ddx[F(x)]ab=ddx[F(b)-F(a)]

=0 [ Fb-Fais a constant and derivative of a constant is 0]

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