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Verify that ∑k=1nk2isequalton(n+1)(2n+1)6for the cases (a)n=1,(b)n=5,(c)n=10

Short Answer

Expert verified

Part(a)Forn=1,∑k=1nk2=n(n+1)(2n+1)6Part(b)Forn=5,∑k=1nk2=n(n+1)(2n+1)6Part(c)Forn=10,∑k=1nk2=n(n+1)(2n+1)6

Step by step solution

01

Part(a) Step 1. Given Information   

The given sum is∑k=1nk2

02

Part(a) Step 2. Calculation   

The left-hand side sum and the right-hand side sum is as follows,

∑k=11k2=1Andn(n+1)(2n+1)6=1(1+1)(2(1)+1)6=66=1

Thus, it is verified.

03

Part(c) Step 1. Calculation   

The left-hand side sum and the right-hand side sum are as follows,

∑k=15k2=12+22+32+42+52=55Andn(n+1)(2n+1)6=5(5+1)(2(5)+1)6=5×6×116=55

Thus, it is verified.

04

Part(c) Step 1. Calculation   

The left-hand side sum and the right-hand side sum are as follows,

∑k=110k2=12+22+32+42+52+62+72+82+92+102=385Andn(n+1)(2n+1)6=10(10+1)(2(10)+1)6=10×11×216=385

Thus, it is verified.

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