Q 15. Explain why the sum 鈭慿=120f-3+... [FREE SOLUTION]

Chapter 4: Q 15. (page 339)

Explain why the sum ${鈭�}_{k = 1}^{20} f (- 3 + \frac{k}{2}) (0.25)$ can't be a right sum for $f$ on $[a, b] = [- 3, 2]$

Short Answer

Expert verified

The sum ${鈭�}_{k = 1}^{20} f (- 3 + \frac{k}{2}) (0.25)$ can't be a right sum as part of the sum ${鈭�}_{k = 1}^{20} f (- 3 + \frac{k}{2}) (0.25)$ indicates that $鈭� x = \frac{1}{2}$

Step by step solution

Step 1. Given information

${鈭�}_{k = 1}^{20} f (- 3 + \frac{k}{2}) (0.25)$ is the sum.

Step 2. Explanation

Consider the sum ${鈭�}_{k = 1}^{20} f (- 3 + \frac{k}{2}) (0.25)$

${鈭�}_{k = 1}^{20} f (- 3 + \frac{k}{2}) (0.25) = f (- 3 + \frac{1}{2}) (0.25) + f (- 3 + \frac{2}{2}) (0.25) + f (- 3 + \frac{3}{2}) (0.25) + . . .$

Here, part of the sum denotes that $鈭� x = \frac{1}{2}$ and the other part indicates 0.25

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Explain why the sum ${鈭�}_{k = 1}^{20} f (- 3 + \frac{k}{2}) (0.25)$ can't be a right sum for $f$ on $[a, b] = [- 3, 2]$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Explanation

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91影视

Explain why the sum 鈭�k=120f-3+k2(0.25) can't be a right sum forfona,b=-3,2

Short Answer

Step by step solution

Step 1. Given information

Step 2. Explanation

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Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Probability and Statistics

Decision Maths

Calculus

Applied Mathematics

Mechanics Maths

Study anywhere. Anytime. Across all devices.

Explain why the sum ${鈭�}_{k = 1}^{20} f (- 3 + \frac{k}{2}) (0.25)$ can't be a right sum for $f$ on $[a, b] = [- 3, 2]$