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Write the sum 47+58+69+710+811in sigma notation in three ways: with a starting value of(a)k=4,(b)k=7,(c)k=5

Short Answer

Expert verified

Part(a)∑k=48kk+3Part(b)∑k=711k-3kPart(c)∑k=59k-1k+2

Step by step solution

01

Part(a) Step 1. Given Information 

The given sum is47+58+69+710+811

02

Part(a) Step 2. Calculation

The sum can be written as follows,

47+58+69+710+811=44+3+55+3+66+3+77+3+88+3=∑k=48kk+3

03

Part(b) Step 1. Calculation

The sum can be written as follows,

47+58+69+710+811=7-37+8-38+9-39+10-310+11-311=∑k=711k-3k

04

Part(c) Step 1. Calculation

The sum can be written as follows,

47+58+69+710+811=5-15+2+6-16+2+7-17+2+8-18+2+9-19+2=∑k=59k-1k+2

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