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If a continuous, differentiable function f has values f (−2) = 3 and f (4) = 1, what can you say about f ' on [−2, 4]?

Short Answer

Expert verified

f is continuous and differentiable on -2,4and satisfied all conditions of Rolle's theorem .

Step by step solution

01

Step 1. Given information .

Consider the given points of function f-2,4.

02

Step 2. Find function f to satisfy the given conditions .

fx=x+2x-4has roots x=-2,x=4.

The function that satisfied the conditions of Rolle's theorem is fx=x2-2x-8Since f is a polynomial, it is continuous and differentiable. In particular, it is continuous on -2,4.

Therefore Rolle’s Theorem applies to the function f , and we can conclude that there must exist some value of c ∈ (−2, 4) for which f '(c) = 0. At this value f will have a horizontal tangent line .

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