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determine the global extrema of functionfx=x2ln0·2x,I=0,4,J=0,∞

Short Answer

Expert verified

On I, f has a global maximum at x=0 and a global minimum at x=5e

On J, f has no global minimum atx=5eand has no global maximum

Step by step solution

01

Step 1. Given information

The given function isfx=x2ln0·2x

02

Step 2. Calculate global maximum and minimum

fx=x2ln0·2xf'x=0dx2ln0·2xdx=0x2·10·2x×0·2+ln0·2x×2x=0x1+2ln0·2x=0x=0;x=e-120·2x=0;x=5eAgain,limx→0fx=limx→0x2ln0·2x=limx→010·2x×0·2-2x3=limx→0-1x·x32=limx→0-x22Againlimx→∞fx=limx→∞x2ln0·2x=∞

03

Step 3. The solution

On I, f has a global maximum at x=0 and a global minimum at x=5e

On J, f has no global minimum at x=5eand has no global maximum

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