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Suppose that fis defined for x=0and differentiable everywhere except at x=0and x=1, and that f'(x)=0only at x= ±2. List all the critical points of f and sketch a possible graph of f.

Short Answer

Expert verified

f(x)=0.2x5−0.25x4−1.33x3−2x2

Step by step solution

01

Step1. Given Information

The function is defined forx≠0and is differentiable at all points except atx=0andx=1and thatf′(x)=0only atx=±2

02

Step 2. Calculations

The critical points of the function, therefore will bex=−2;x=0;x=1;x=2Therefore, the differentiation of the function will bef′(x)=x(x+2)(x−2)(x−1)The graph can be drawn as

Therefore, the function isf(x)=0.2x5−0.25x4−1.33x3−2x2

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